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A tree diagram consist of an element from wich 1 or more other elements are derived, these elements could also divide in 1 or many others until an element from wich nothing derives is reached. The following example represents a general tree diagram.
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\begin{forest}
...
\end{forest}
The element following the root are considered from left to right.
Every element of a tree can be considered as a root for a subtree, for example a0 in the last image can be considered as a root to the following tree:
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The root must be inside square brackets that must also contain all elements that derive from it. To start let's make a tree with a root and three following elements.
\begin{forest}
[Root
[Left]
[Center]
[Right]
]
\end{forest}
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\begin{forest}
[Root
[Left]
[Center
[center-left]
[center-right]
]
[Right]
]
\end{forest}
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The first option will align all leaves:
\begin{forest}
for tree={
if n children=0{
font=\itshape,
tier=terminal,
}{},
}
[Root
[$a_1$
[$b_1$]]
[$a_2$
[$b_1$
[$c_1$]
[$c_2$]
[$c_3$]]]
[$a_3$
[$b_1$
[$c_1$]
[$c_2$
[$d_1$]
[$d_2$]]]]]
\end{forest}
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\begin{forest}
for tree={draw,circle,dotted,blue
if n children=0{
font=\itshape,
tier=terminal,
}{},
}
[Root
[$a_1$
[$b_1$]]
[$a_2$
[$b_1$
[$c_1$]
[$c_2$]
[$c_3$]]]
[$a_3$
[$b_1$
[$c_1$]
[$c_2$
[$d_1$]
[$d_2$]]]]]
\end{forest}
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[Node,tikz={\node [draw,red,inner sep=0,fit to=tree]{};}...
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To check that all these new concepts have been understood i would
like to invite the reader to try and replicate the following diagram using
Latex.
for tree={draw,
if n children=0{
font=\itshape,
tier=terminal,}{},}
[Root
[$a_1$ ,tikz={\node [draw,circle,green,inner sep=0,fit to=tree]{};}
[$b_1$
[$d_1$]
[$d_2$]
[$d_3$]]]
[$a_2$
[$b_1$
[$d_4$]
[$c_1$
[$d_5$]
[$d_6$]]]]]